//Program to find sum of squares of n natural numbers
#include<iostream>
using namespace std;
int main()
{
int n,sum;
cout<<"\n enter upto which number you want to find sum of squares:";
cin>>n;
sum=(n*(n+1)*(2*n+1))/6;
cout<<"\n sum of squares of "<<n<<" natural numbers is : "<<sum<<endl;
return 0;
}
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06 August 2018
C/C++ Program to find sum of squares of n natural numbers
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