// Program to find a given number is even (or) odd.
#include<iostream>
using namespace std;
int main()
{
int n,i,is_even=0;
cout<<"\n enter a number"<<endl;
cin>>n;
for(i=2;i<n;i++)
{
if(n%2==0)
is_even=1;
}
if(is_even)
cout<<n<<" is an even"<<endl;
else
cout<<n<<" is an odd"<<endl;
return 0;
}
02 August 2018
C/C++ Program to find a given number is even (or) odd.
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